Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
0
Why are these being used more than once?
I want each letter to only be used once when it prints on the last line, but it does some letters more than once, why?
local Pool={"a","b","c"}
Pool[1] = Pool[math.random(1,#Pool)]
local OM1 = Pool[1]
table.remove(Pool, 1)
Pool[1] = Pool[math.random(1,#Pool)]
local OM2 = Pool[1]
table.remove(Pool, 1)
Pool[1] = Pool[math.random(1,#Pool)]
local OM3 = Pool[1]
table.remove(Pool, 1)
print(OM1,OM2,OM3)
1 answer
Log in to vote
1
Each time, you're replacing the first element with a random one. This eliminates the first one at each step from being truly chosen later. You then eliminate that copy instead of the original.
That will look like this:
{a, b, c}
{c, b, c} -- Pool[1] = Pool[3]
{b, c} -- table.remove(Pool, 1)
{c, c} -- Pool[1] = Pool[2]
{c} -- table.remove(Pool, 1)
Here is how you remove a random thing from a list:
local O1 = table.remove(Pool, math.random(#Pool))
Note that the 1, is optional in math.random.
0
I'm sorry, but where would I use this? I don't quite understand ItsMeKlc 235 — 8y
0
Sorry, had a typo in the correct line. It's also a little clearer now. BlueTaslem 18071 — 8y
0
I still don't understand... Do I replace my lines 4,8,12 with this? ItsMeKlc 235 — 8y
0
I give a line explaining how to get and remove a random thing from a list. It defines `O1`. You can infer that would replace the stuff you use to modify Pool and get OM1. You can then infer that since `1` is not part of it, you can reuse this same line to make OM2 and OM3. BlueTaslem 18071 — 8y
0
Oh okay. Thank you so much! ItsMeKlc 235 — 8y