Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
1
Tweening Color3 values in sequence?
So I'm trying to create a smooth transition between Color3 values, in a rainbow-like effect. I've come up this conclusion:
local function TweenColor(gui,new,prop,time)
local v = gui[prop]
time = time * 30
local saved = {
r=new.r-v.r;
g=new.g-v.g;
b=new.b-v.b;
}
for i = 1,time do
gui[prop] = Color3.new(
gui[prop].r+saved.r/time,
gui[prop].g+saved.g/time,
gui[prop].b+saved.b/time
)
wait()
end
end
This will tween color A, to color B very smoothly. However, I still have yet to figure out a compact way to make a rainbow effect and have the function tween through all it's colors.
If anyone knows a good way to accomplish this, I'd very much appreciate it. Thanks.
0
well a rainbow starts at red and goes to blue so start increasing red then increasing green and decreasing red and then the same with blue maybe ProfessorSev 220 — 8y
1 answer
Log in to vote
4
ProfessorSev's comment isn't far off. For the effect you're looking for, you could cycle the hue value and convert to RGB, as follows:
local hue = 0; -- this will cycle from 0-359
local SAT = 1; -- satutation; constant
local LUM = 1; -- luminance; constant
local SPEED = 1; -- hue degree/frame
function hsvToRgb(h, s, v) -- from https://github.com/EmmanuelOga/columns/blob/master/utils/color.lua - essentially ramps different values depending on which sixth 'h' is in
local r, g, b
local i = math.floor(h * 6);
local f = h * 6 - i;
local p = v * (1 - s);
local q = v * (1 - f * s);
local t = v * (1 - (1 - f) * s);
i = i % 6
if i == 0 then r, g, b = v, t, p
elseif i == 1 then r, g, b = q, v, p
elseif i == 2 then r, g, b = p, v, t
elseif i == 3 then r, g, b = p, q, v
elseif i == 4 then r, g, b = t, p, v
elseif i == 5 then r, g, b = v, p, q
end
return r, g, b
end
-- the rainbow effect:
while (true) do
color = hsvToRgb(hue/360, SAT, LUM);
hue = (hue+SPEED)%360;
wait()
end
That could be severely simplified, but the main loop is basically the logic.