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How would you make a randomized chance to spawn for example a golden brick?
What do you need to do ?
A for loop ? math.random() ?
Some help on here please.
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`math.random(1,chance)` would be your best bet. ChemicalHex 979 — 9y
3 answers
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2
math.random()
If you wanted it to be, say, a 1 in 5 chance:
1 | if math.random() <= 1/5 then |
2 | -- Boom, golden brick! |
3 | end |
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I mean, I myself would use Int Values and math.random
1 | if math.random(1, 100) <= script.Chance.Value then |
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Will not quite work as expected if Chance is a decimal value. math.random generates integers. If chance was set to 1.99 (1.99%), it would effectively have a 1% probability of occurring. Furthermore, chances under 1% will always have a 0% probability of occurring. XAXA 1569 — 9y
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Another way of solving this is to have some sort of rarity variable, where a golden brick has a 1 in rarity chance of appearing. Making the rarity of the brick bigger means that it is more rare!
1 | local GOLDEN_BRICK_RARITY = 100 -- this means that 1 in 100 bricks spawned will be golden. Setting this to 1 means a golden brick will ALWAYS spawn. |
2 |
3 | function SpawnBrick() |
4 | if math.random(1, GOLDEN_BRICK_RARITY) == 1 then |
5 | -- TODO: Spawn a golden brick |
6 | else |
7 | -- TODO: Spawn a regular brick. |
8 | end |