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2
"Plr" returns nil?
I'm trying to learn string.match and this script looks correct, but it returns nil.
01 | wait() |
02 | local player =game.Players.LocalPlayer |
03 | local players =game.Players:GetChildren() |
04 |
05 | function match_name(name) |
06 | for i,v in pairs(players) do |
07 | local plr=string.match(v.Name,name) |
08 | if plr then |
09 | return plr |
10 | end |
11 | end |
12 | end |
13 |
14 | player.Chatted:connect(function(msg) |
15 | if string.sub(msg,1,6)=="check~" then |
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2 answers
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2
You have to return v, because that is the player, instead of plr, which is the string.
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0
In Lua, although not in every language, it is safe to directly compare strings, so that string.match() is not the best way to solve this problem.
Additionally, your check~ command will never return anything anyway, because you make players an empty Table (since game.Players is empty when this script first runs) and then never update it.
01 | wait() |
02 | local player = game.Players.LocalPlayer |
03 |
04 | function match_name(name) |
05 | for i,v in pairs(players) do |
06 | if plr.Name == name then |
07 | return v |
08 | end |
09 | end |
10 | end |
11 |
12 | player.Chatted:connect(function(msg) |
13 | if string.sub(msg,1,6) == "check~" then |
14 | local plr=match_name(string.sub(msg,7)) |
15 | if plr then |
16 | print(plr.Name) |
17 | end |
18 | end |
19 | end) |
This page has the most comprehensive documentation of string patterns, which is what I assume you're trying to learn here.