Brick tweening (Lerp)?

Vector3:Lerp takes two args, where the end position is, and the alpha. The alpha is a number between 0 and 1. It's how far between the start and end point the returned value is.

To get the value between two values we would do

Vector3.new(0, 0, 0):Lerp(Vector3.new(0, 10, 0) -- Vector3.new(0, 5, 0)

So if you want a value to tween(interpolate, lerp, ease, they all mean relatively same thing) between two points you would use a loop

local start = Vector3.new(0, 0, 0)
local finish = Vector3.new(0, 10, 0)
for i = 0, 1, .1 do
    brick.Position = start:Lerp(finish, i)
    wait()
end

It's also worth noting that Lerp means linear interpolation. It takes a straight path from start to end, it uses the formula a + (b - a) * alpha

There's a lot of different formulas to tween, linear is the most basic but there's a lot better ones to use for smooth transitions.

local PartYouWantToMove = game.Workspace.Part;
local framesItWillTakeToFinish = 30;
local finalCFrame = CFrame.new(0, 0, 0)
local finalCFrameAngles = CFrame.Angles(math.rad(0), math.rad(0), math.rad(0))

for i = 1, framesItWillTakeToFinish do
PartYouWantToMove.CFrame = PartYouWantToMove.CFrame:Lerp(finalCFrame*finalCFrameAngles), i*1/framesItWillTakeToFinish)
game["Run Service"].RenderStepped:wait()
end

Okay, so here, the framesItWillTakeToFinish is what it says. usually, youll get 60 fps, so if you set it to 30, then it will take 0.5 seconds for the part to go from its original position to get to its final position. The final cframe is where you want the part to go (position), and the finalCFrameAngles (along with the math.rad() to convert it to degrees) will let you tell the script what angle you want the part to be at once its completed. the game["Run Service"].RenderStepped:wait() is a cheeky way to make a wait(), but instead of 1/30th of a second, its one frame (so like 1/60th of a second.) The last number is how far along the part is along its lerp, so 0 will be the beginning and 1 will be the end. You always want this to match up with how many times you will run the for i = 1, ----- stuff.