How can I split all players evenly into 2 teams?
How would I split players evenly (or as evenly as you can if there is a odd number) into 2 teams. I know how to put people into teams and create them with a script. Just in not sure how to split all the players evenly.
Is it like for i = .... I'm not sure Please help!
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3 answers
Okay, this can get a bit complex, so i'll try to explain all the necessary elements
Overview
We're going to be using a bit of math in this example, so if math isn't your subject, you should pay extra close attention. Now, to get the even amount of teams, we can basically sum it up in 1 equation:
Players % Teams
However, this equation is only valid if we use it correctly. The only reason this equation is relevant, is because of an array we'll be using.
Wait, what does the "%" do?
The % symbol (or, modulus) is an arithmetic operator that returns the remainder of 2 divided numbers. I'll explain why this can be useful later on.
What's an array?
An array is a table consisting of numeric keys. These numeric keys represent the value's position in the table, which makes it super easy for us to access them when using arithmetic operations.
When we index an array with a numeric key, it will return the value that key represents (as any kind of table would).
So, we can easily apply this useful knowledge to our equation:
01 | -- Set up some services |
02 | local _Teams = game:GetService'Teams' |
03 | local _Players = game:GetService'Players' |
04 |
05 | -- Teams |
06 | -- Just gets all teams from the team service. |
07 | -- Note, this returns an ARRAY of teams. (thus, my explanation on arrays) |
08 | local Teams = _Teams:GetTeams() |
09 |
10 | -- Get players |
11 | -- Returns all players |
12 | local function GetPlayers() |
13 | return _Players:GetPlayers() |
14 | end |
15 |
The "Teams" table
Now, since "Teams" is an array, we can index it with a numeric key. In this case, our numeric key being the remainder of #Players / #Teams.
It probably sounds like a bit much all at once, but i'd be happy to explain any questions you may have about this code. This will also work for any amount of teams, not just 2.
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Well, personally, I'd create 3 tables. 1 for Team 1, 1 for Team 2, and 1 for players. Since you didn't prove any attempts at scripting this, I'll provide you some tips. Create a function to determine if there is an even amount of players, or not. With that, you can either split the players directly in half, or randomize it to your liking. As you choose them, remove them from the Players table, into a team table. After one team is settled, move the remaining players in the table, to team 2. After your tables are complete, use a simple for loop, to team them all to the corresponding team. There you go!
Problem You need to put some scipt in it here you go though
Solution
01 | function scramble(team1color,team2color) -- the variables need to be like "Black" or white" |
02 | team1 = {} |
03 | team2 = {} |
04 | check = 0 |
05 | for i,v in pairs(game.Players:GetChildren()) |
06 | if check == 0 then |
07 | table.Insert(team1,#team1+1,v) |
08 | check =1 |
09 | end |
10 | if check == 1 then |
11 | table.Insert(team1,#team2+1,v) |
12 | check =0 |
13 | end |
14 | end |
15 |
tell me if this works, if not just message me the error
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