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How do I check the first 7 characters of a string, in a concise form?
If the word is Solider how would I do it,
Without doing this:
String = "soldier1"
Name = {"s", "o", "l", "i", "d", "e", "r")
for i, in String do
if String[i] = Name[i] then
print (..i.. "Ok")
-- This is rough I just done it now, this isn't supposed to be accurate.
1 answer
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This uses the sub method of the string class.
Change s1 and s2 to whatever you want. Also change the num variable for the number of letters you want to check.
local s1 = "soldier1"
local s2 = "soldier"
local num = 7
if #s1 >= num and #s2 >= num then
if s1:sub(1, num) == s2:sub(1, num) then
-- first {num} letters are the same
end
end