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Still Problems, Help with Tool Problems?

Asked by
TayLife12 69
9 years ago

I am trying to make a machine to where if the tool Colors are equal to what the script says it will change the name... but it wont work for some reason? I have tried different ways but none have been helping me....

What will happen is when the handle touches it if Filling one and Filling two are equal to the Color in the Script then it will change the tool name

h is the tool handle Filling One And Filling Two Are Not Children Of The Tool

function tch(h)
if h.Name == "Handle" and h.Parent.FillingOne.BrickColor == "Nougat" and h.Parent.FillingTwo.BrickColor == "Reddish brown" then
    script.Parent.Sound:play()
    wait(2.5)
    script.Parent.Sound:Stop()
    h.Parent.Name = "Butterfinger Blizzard"
end
end

script.Parent.Touched:connect(tch)

When I go to do it In the output it now pops up,

"10:02:09.097 - FillingOne is not a valid member of Part"

Can someone help me?

1 answer

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Answered by
HungryJaffer 1246 Badge of Merit Moderation Voter
9 years ago 
function tch(hit)
   if hit and hit.Name == "Handle" then
       if hit.Parent:IsA("Tool") and hit.Parent:findFirstChild("FillingOne") and hit.Parent:findFirstChild("FillingTwo") then
            local filling = hit.Parent.FillingOne
            local filling2 = hit.Parent.FillingTwo

            if filling.BrickColor == BrickColor.new("Nougat") and filling2.BrickColor == BrickColor.new("Reddish brown") then
                script.Parent.Sound:play()
                wait(2.5)
                script.Parent.Sound:Stop()
                h.Parent.Name = "Butterfinger Blizzard"
            end

       end

   end
end

script.Parent.Touched:connect(tch)

I edited ImageLabel's script to work. I explained all of this to you in the chat.

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It Worked! Thank you so much! TayLife12 69 — 9y
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