Output showing Table.remove() Problems?

The table.remove function only removes values from a list. It will not search through the table looking for the value to match the second argument. It looks for the key, which is suppose to be a number.

Example:

local list = {
    "pie",
    "ice cream",
    "candy",
}

table.remove(list, 2) -- this will remove "ice cream" because it's index value is 2.

If you want to make it so you remove a value from a table based on it's value, you can write a separate function that compares every value in the table to an argument you give it.

Like this:

local list = {
    "pie",
    "ice cream",
    "candy",
}

local function remove_value(Table, Value)
    for i,v in pairs (Table) do
        if v==Value then
            table.remove(Table,i)
        end
    end
end

remove_value(list, "pie")

print(unpack(list)) -- > "ice cream" , "candy"