Split a string when a certain character is found?
For example:
local levelInfo = "1_1" is the string I'm using. How would I split the string so I get two variables for the first 1 and the second 1, because there is a '_' in the middle of it?
Not sure this is possible with string.sub because the 1 may be a two-digit number and I don't think it can detect when there is a certain character.
2 answers
You can use string.find to find where the underscore is and then split the string using string.sub.
string.find returns at what character position a pattern is found. A pattern can be any string (in your case it would be _). Once the pattern is found, you can use string.sub to get the substrings using the information from string.find as your divider.
1 | local levelInfo = "1_1" |
2 |
3 | local divider = string.find(levelInfo, "_") --levelInfo is your string and "_" is your divider. The variable "divider" is now the numerical position of the pattern "_" in the string, |
4 | local substring1 = string.sub(levelInfo, 1, divider - 1) --I'm assuming you know what string.sub does since you mentioned it in your question.. You have to subtract one from "divider" because "divider" would equal the position of "_" and you want everything before that. |
5 | local substring2 = string.sub(levelInfo, divider + 1, string.len(levelInfo)) --Use the same thing as the line above, but divider + 1 is the starting position (add 1 because divider is equal to "_") and the ending position is the total number of characters inside the string (received from string.len). |
Here is more information on string.find.
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