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How would I change the size of a part in a certain direction?
I've tried to figure this out many times and I just can't seem to do it. I know that this code below:
1 | part = script.Parent |
2 |
3 | for i = 1,10,1 do |
4 | part.Size = Vector3.new(part.Size.X + 1,part.Size.Y,part.Size.Z) |
5 | wait(0.1) |
6 | end |
-changes the size of the part but it changes in the direction of negative X and positive X, but I just want it to change only on the direction of positive X. How could I do that?
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Go here for help http://wiki.roblox.com/index.php?title=API:Class/BasePart/Resize The first parameter is the side, which is 0 - 5, the second part is how many studs\ legobuildermaster 220 — 9y
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That didn't really help. alex_ander 163 — 9y
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Try using part:Resize(0, 1) or part.Resize(0, 1) legobuildermaster 220 — 9y
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It worked but it's only resizing it by 1. I want it to resize now by 0.2. alex_ander 163 — 9y
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Then just write 0.2 instead of 1..... Scriptree 125 — 9y
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Ugh so dumb, it only works with whole numbers. alex_ander 163 — 9y
2 answers
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1 | local Part = script.Parent |
2 | local AddNumber = 1 --The amount of studs added in each loop. |
3 | local SizeAddition = 10 --How many times the script adds "AddNumber". |
4 |
5 | for i = 1,SizeAddition do |
6 | wait() |
7 | Part.Size = Vector3.new(Part.Size.X + AddNumber,Part.Size.Y,Part.Size.Z) |
8 | Part.CFrame = Part.CFrame - Vector3.new(AddNumber/2,0,0) |
9 | end |
I think this is what you are looking for.
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The following method will work:
1 | local part = script.Parent |
2 |
3 | for i = 1, 10 do -- u dont need the "1" after the 10, because it already goes up by ones without that |
4 | part.Size = part.Size + Vector3.new(1, 0, 0) -- so here you are making the Size of the part the same, but just adding to the x, or y, or the z axis, this adds 1 stud every 1/30 seconds to the x axis |
5 | wait() -- wait() is the least wait you can have in a server script which is also equivalent to wait(1/30) |
6 | end |
Hope it helped :)