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Getting the highest block of the specific x and z coordinates quickly?

Asked by 9 years ago

I have a system of chunks and folders. I use the folders for storing data and using their names to store a position. Examples of the names are below: 1. 0, 0.045, 0
2. 0, 2.045, 0
3. 1, 5.676, 10

Now here is what I currently have:

Module.GetHighestGrassBrick = function(X, Z) -- Used for trees currently
    local RegionX, RegionZ = LocateRegion(Vector3.new(X, 0, Z))
    local Region = RegionData:findFirstChild("Region"..RegionX.."-"..RegionZ)
    local CurrentHeight = 0
    for Number, BrickFolder in pairs(Region:GetChildren()) do
        if BrickFolder:IsA("Folder") then
            local XX, YY, ZZ = GiveCoords(BrickFolder)
            if XX == X and ZZ == Z and YY > CurrentHeight and (BrickFolder:GetChildren())[1].Name == "Grass" then
                CurrentHeight = YY
            end
        end
        if Number%4096*8 then wait() end
    end
    return CurrentHeight
end

Due to the nature of this, it takes roughly 5 seconds of sorting through 131,072 folders and checking the x and z coordinates, then comparing the height with the current highest spot. Of course nothing will move until it's done.

The regionX is the chunk's X and the regionZ is the chunk's Z, those aren't needed for you guys. I need a mroe efficent way to do this, I can redo the folder structure, but if possible this is a better structure for my purposes.

Keep in mind, 5 seconds of nothing moving is fine and all, but it does this 10 times....

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