How to make Smoother Terrain Generation (Using bricks)?
I have a basic script that allows for a given width and height of cubes, and for the baseplate size. Now what I was wondering is how to smooth the slopes, rather than using math.random to give me random heights.
local width = 2
local height = 2
local baseplate = {30, 30}
local model = Instance.new("Model")
model.Parent = game.Workspace
model.Name = "Terrain Parts"
local bricksRemove = game.Workspace:FindFirstChild("Terrain Parts"):GetChildren()
for num, obj in pairs(bricksRemove)do
if obj:IsA("Part") then
if obj.Name == "Terrain Blocks" then
obj:Destroy()
end
end
end
for i = 0, ((baseplate[1]/width)*(baseplate[2]/width))-1 do
local brick = Instance.new("Part")
brick.FormFactor = 3
brick.Size = Vector3.new(width, height, width)
brick.Position = Vector3.new((i%(baseplate[1]/width))*width, math.random()+4, math.floor(i/(baseplate[2]/width))*2)
brick.Anchored = true
brick.Name = "Terrain Blocks"
brick.Parent = game.Workspace:FindFirstChild("Terrain Parts")
end
I was debating whether getting blocks at certain intervals and using them to decide the incline/decline then smooth the blocks within a given range to that, but that didn't seem efficient. So if anyone has any information that will guide me into making smooth terrain, I would be grateful.
~ Legobuildermaster
0
1 answer
First, you should simplify this code a little.
Clearing the children can be much simpler:
* There's no point to :FindFirstChild if you immediately call :GetChildren
* You shouldn't have the space in the name in the first place.
* You should just use ["Terrain Parts"] if you insist on having the space
* You can combine the two ifs using and to save two lines and a level of indentation
* No need to use a name like num if you aren't going to use it
* You should use workspace instead of game.Workspace
* You should probably use "TerrainBlock" instead of "Terrain Blocks"
* each is one Block; each is not several Blocks
* it's not normal for names to have spaces in them
for _, child in pairs(workspace.TerrainParts:GetChildren()) do
if child:IsA("BasePart") and child.Name == "Terrain Blocks" then
child:Destroy()
end
end
You can iterate over the grid much more easily, too. You don't need i itself, you just need the x and y. I would recommend not using baseplate or width or height because the names are very unclear. I would recommend blockWidth and blockHeight to describe sizes of individual blocks and worldX and worldZ or similar to describe the size of the world.
It's also easier to talk about x and y
for x = 0, worldX, blockWidth do
for z = 0, worldZ, blockWidth do
local brick = Instance.new("Part")
brick.FormFactor = "Custom" -- Use descriptive values!!
brick.Anchored = true
brick.Size = Vector3.new(blockWidth, blockHeight, blockWidth)
local y = math.random() * 4
brick.Position = Vector3.new(x, y, z)
brick.Name = "TerrainBlock"
brick.Parent = workspace.TerrainParts
end
end
Now, you need y to just be a function of x and z.
There are tons of different ways to do terrain generation. Recently ROBLOX added math.noise which gives you access to Perlin noise. You could use it something like this:
function height(x, y)
return (math.noise(x / 20, y / 20) + math.noise(x / 35, y / 35) + math.noise(x / 77, y / 77)) * 10
end
....
local y = height(x, z)
brick.Position = Vector3.new(x, y, z)
....
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