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1
Question for shawnyg?
1 | decay = decay * 0.9 |
Trying to make decay go down by 10% repeatedly without making tons of decimals after it goes down a few times.
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0.9 is 90 percent. And shawny is correct, can't multiply a word by a number! alphawolvess 1784 — 9y
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How come the question is ONLY for Shawnyg? You can't do that, Once there was a question that was only for BlueTaslem and he himself said that you can't ask certain people to answer your question ONLY. EzraNehemiah_TF2 3552 — 9y
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cuz shawny is an intelligent man unmiss 337 — 9y
2 answers
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1
Well, you'd need to use a loop. Since you have no other code, I recommend you use a while loop!
1 | decay = 2 -- Make sure to Set the value first! |
2 |
3 | while wait(1) do |
4 | decay = decay - (decay * .10) |
5 | end |
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Since * 0.9 is the same as -10%, the decimal problem is still there. And how it repeats isnt relevant. drew1017 330 — 9y
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If you want it to be a whole number, you could use math.floor to round down! http://wiki.roblox.com/index.php?title=Math.floor#math.floor Shawnyg 4330 — 9y
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This can take a helluva lot of string manipulation and math, which can cause a helluva lot of frustration. I got it though.
01 | decay = 10 --Initial value. |
02 | decayfactor = .1 --Rate of decay. |
03 | placesafterdecimal = 3 --Places after decimal. |
04 |
05 | while wait(1) do |
06 | decay = decay - (decay*decayfactor) |
07 | stringdecay = tostring(decay) |
08 |
09 | if string.find(stringdecay, ".") then |
10 | local decimal = string.find(stringdecay, ".") |
11 | local afterdecimal = string.sub(stringdecay, decimal + 2, string.len(stringdecay)) |
12 |
13 | if string.len(afterdecimal) > placesafterdecimal then |
14 | afterdecimal = tostring(math.floor(tonumber(afterdecimal)/10^(string.len(afterdecimal)-placesafterdecimal))) |
15 | end |
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