How to trigger if string = any number?

So you want to see if a string has ANY numbers in it?

One way to do this is use the tonumber function. This function turns any given string into a number, if the given string has non-numerical characters in it then the tonumber function will return nil, so it's suggested that you don't use this method.

local str = '420'

print(tonumber(str)) -->420
print(type(tonumber(str))) --> number

--If it's not soley a number

local str = 'Four20'

print(tonumber(str)) --> nil
print(type(tonumber(str))) --> nil

--[[
    The 'type' function returns what datatype the given arguments are(:
    type('') --> string
    type({}) --> table
    type(function() end) --> function
    etc..
]]--

Another way to do this is to use the string.gmatch function. This function lets you use string patterns to return a matching string. If you use this function in a generic for, then you can use %d+ as a pattern detector.. this pattern detector gets any numbers - and the + operator gets grouped numbers(:

local str = 'H3llo my n4m3 15 G0u15t3m'
local matches = {}

for i in str:gmatch('%d+') do
    table.insert(matches,i)
end

print(unpack(matches)) -->3 4 3 15 0 15 3

And if i'm going overkill on this and all you need is to see if a string is equal to a wanted number then just compare the string to a preset number variable using tostring

local num = 420
local str = '420'

if tonumber(str) == num then
    --code
end

--And vise-versa(;

if tostring(num) == str then
    --code
end