Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
0
how to remove recent child added ?
on my inventory there is limited space but every child added creates a new button... i got a counter that is 24 but i want when the counter reaches 24 it will remove any recent child added until counter is below 24
local P = game.Players.LocalPlayer;
repeat wait() until P.Character;
local C = P.Character;
local gui = script.Parent
local menu = gui.Inventory
local folder = menu.Folder
local KeepHats = folder.KeepHats
local ply = gui.Parent.Parent
local inven = menu.Core
local openclose = gui.Button
local Button = folder.Button
repeat wait() until gui.Parent.Parent:FindFirstChild("Inventory")
function getMyPack()
return gui.Parent.Parent.Inventory
end
function removeOldOutOfTheWay(objects)
for _, child in pairs(objects) do
if child.Name == "Button" then
child:Destroy()
end
end
end
function UpdateInventory()
removeOldOutOfTheWay(inven:getChildren())
if script.Parent.Inventory.Options.Counter.Value <= 24 then
local x, y = 0, 0
local pack = getMyPack()
local lo = pack:getChildren()
for _, child in pairs(lo) do
local neww = Button:Clone()
neww.Position = UDim2.new(x, 0, y, 0)
neww.Item.Value = child.Name
neww.ID.Value = child.Value
neww.Class.Value = child.Price.Value
neww.Parent = inven
x = x + 0.265
if x > 0.8 then
y = y + 0.17
x = 0
end
end
end
end
local pack = getMyPack()
pack.ChildAdded:connect( UpdateInventory )
1 answer
Log in to vote
0
Use a dictionary and workspace.DistributedGameTime. Whenever there's too much inventory, go through the dictionary and find the lowest value; remove that entry.
children = {} --dictionary; key = child, value = time added
--in ChildAdded, assuming a variable "child":
children[child] = workspace.DistributedGameTime
--When you want to remove a child:
local lowestKey = nil
local lowestValue = nil
for k, v in children do
if not lowestValue or v < lowestValue then
lowestKey = k
lowestValue = v
end
end
children[lowestKey] = nil
lowestKey:Destroy()