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1
[Solved]How would I detect if one of the three values are the highest?
1 | a = 10 |
2 | b = 1 |
3 | c = 5 |
If people voted and these were the results how would I figure out whats the highest?
2 answers
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3
This is a more complex way, but would be able to work with multiple numbers, or variables. Which could all be set into a table. I know you didn't ask for this exactly but this might help fix the problem or help in the future.
01 | local a = 10 |
02 | local b = 1 |
03 | local c = 5 |
04 |
05 | local Dictionary = {"a", "b", "c", "d", "e", "f", "g", "h", "I", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"} |
06 |
07 | function Compare(Args) |
08 | local HighestNumber = nil --The highestnumber out of the table |
09 | local Letter = nil --The letter that goes with the highestnumber like A,B,C, etc. |
10 | for I,v in pairs(Args) do --Grabs all of the variables from the table, and cycles until it's read through eah variable. |
11 | if HighestNumber == nil then |
12 | HighestNumber = v |
13 | Letter = Dictionary[I] |
14 | else |
15 | if v > HighestNumber then |
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0
Sorry about the capital I's, most of them are suppose to be lower cased. But my computer automatically capitalizeses I's. xImmortalChaos 565 — 10y
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thx anyways rabidhalofan12345 55 — 10y
1
Np, hope you can understand that in some ways. Thought it would just be cool to show you how you can expand on that type of stuff. xImmortalChaos 565 — 10y
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1
01 | a = 10 |
02 | b = 1 |
03 | c = 5 |
04 | if a > b and a > c then |
05 | print("a wins") |
06 | else |
07 | if b > a and b > c then |
08 | print("b wins") |
09 | else |
10 | if c > a and c > b then |
11 | print(" c wins") |
12 | end |
13 | wait() |
14 | end |
15 | wait() |
16 | end |
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Change the values around (a,b,c) to test out the script! Hybric 271 — 10y
2
Good idea, but recheck your code. :P There are 'if then end' statements in the each 'if then end' statements; consider changing to 'elseif' for the two inside the first. TheeDeathCaster 2368 — 10y
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Also, post an explanation, not just code. Perci1 4988 — 10y