[Solved]How would I detect if one of the three values are the highest?

This is a more complex way, but would be able to work with multiple numbers, or variables. Which could all be set into a table. I know you didn't ask for this exactly but this might help fix the problem or help in the future.

local a = 10
local b = 1
local c = 5

local Dictionary = {"a", "b", "c", "d", "e", "f", "g", "h", "I", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"}

function Compare(Args)
local HighestNumber = nil --The highestnumber out of the table
local Letter = nil --The letter that goes with the highestnumber like A,B,C, etc.
for I,v in pairs(Args) do --Grabs all of the variables from the table, and cycles until it's read through eah variable.
if HighestNumber == nil then
HighestNumber = v
Letter = Dictionary[I]
else
if v > HighestNumber then
HighestNumber = v
Letter = Dictionary[I]
end
end
end
end
Compare({a, b, c}) --{a,b,c} --A table, it stores the numbers from the variables a,b, and c.

a  = 10
b = 1
c = 5
if a > b and a > c then
print("a wins")
else
if b > a and b > c then
print("b wins")
else
if c > a and c > b then
print(" c wins")
end
wait()
end
wait()
end