Can a dictionary key value (if a table) hold multiple values?
can ignore this stuff if you get question:
/~~~~~~~~~~~~~~~~~ Functions = {
CreateConfiguration = (function(Configurations, Table)
--gets the table of the first parameter
for i, v in pairs(Configurations:GetChildren()) do
--finds if the values classname is a value
if string.find(v.ClassName, "Value") then
--if it make its name a clone of its value
print(v.Name)
Table[v.Name] = v:Clone()
--if it isnt and it is either a folder or configuration class
print(Table)
elseif v:IsA("Folder") or v:IsA("Configuration") then
--then make the values name become
Table[v.Name] = Functions.CreateConfiguration(v, Table)
print(Table[v.Name])
end
print(Table)
end~~~~~~~~~~~~~~~~~
The line 16 for some reason ends up making 2 values when I print the table it makes. I don’t know why this happened.
print log:
~~~~~~~~~~~~~~~~~
["Ammo"] = "*** cycle table reference detected ***",
["Automatic"] = Automatic,
["Bullets"] = Bullets,
["Burst"] = "*** cycle table reference detected ***",
["ClipSize"] = ClipSize,
["Damage"] = Damage,
["FireRate"] = FireRate,
["Magazines"] = Magazines,
["Offset"] = Offset,
["Range"] = Range,
["ReloadTime"] = ReloadTime,
["ToolName"] = ToolName
~~~~~~~~~~~~~~~~~
Burst is the folder then offset and bullets are its children.
2 answers
You are running the function. Now it gets to line 16, waits there and runs the same function again on line 16. Now that you are running it again, it is printing. Because it now is finished, the function you first ran can now resume on line 17 and also Prints.
voilla, you have multiple prints because you are running multiple functions.
Edit: And no, a dictionary key can not hold multiple values
No, you can’t. But you can turn multiple values into a table so it will be one value.
local SomeTable = {
foo = "bar", "boo" --wrong
bar = {"foo", "boo"} --correct
}