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I need to trgger a remote event with desroy() but i have no idea how to do that?
Ive been looking around for a while this is my back up incase i dont find out how to work out this issue, What im trying to do is make a function when the gui gets destroyed, but i dont know how to do it, nor can i find any tutorial or page that can help with this specific situation, all efforts will be appreciated, thank you for taking your time to read this!
01 | local gui = script:WaitForChild("ScreenGui") |
02 | local plr = game.Players.LocalPlayer |
03 | local SG = game.StarterGui |
04 |
05 | gui.Parent = plr.PlayerGui |
06 | script.Parent:RemoveDefaultLoadingScreen() |
07 |
08 | repeat |
09 | wait(.5) |
10 | until game:IsLoaded() |
11 | wait(5) |
12 |
13 | gui.Frame:TweenPosition(UDim2.new(0, 0, -1.5, 0), Enum.EasingDirection.InOut,Enum.EasingStyle.Quad, 1) |
14 |
15 | wait(1) |
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0
(you can see in the end that i got confused on what to do when i tried to fire the client Icy_limxz 14 — 2y
0
Since this is already a local script, line 19 wouldn't make sense since you can't use :FireClient() when already on the client. It looks like you're making a custom loading screen? Check out this: https://developer.roblox.com/en-us/articles/Custom-Loading-Screens Shawnyg 4330 — 2y
1 answer
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1
Hello,
What you can do is connect a function to a ChildRemoved Event and check if the instance you deleted was Gui or something else, you can achieve this by,
1 | local GuiParent = script.Parent.Parent |
2 | local RemoteEvent = game.ReplicatedStorage.RemoteEvent |
3 |
4 | GuiParent.ChildRemoved:Connect(function(RemovedInstance) |
5 | if RemovedInstance.Name == "gui" then |
6 | RemoteEvent:FireServer() |
7 | end |
8 | end) |