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1
How do I compare two GUI's text?
I am just messing around with random numbers and was trying to make a system that would update every time a higher number is generated.
01 | local rtext = script.Parent.Parent.Random |
02 | local htext = script.Parent |
03 |
04 | htext.Text = 0 |
05 |
06 | while true do |
07 | wait(.01) |
08 | if rtext.Text > htext.Text then |
09 | htext = rtext |
10 | end |
11 | end |
When I run this the console says I am trying to compare nil values, is there an easy way to make the text from a GUI into an integer value?
0
on line 8, you may want to change them to “if tonumber(rtext.Name) > tonumber(htext.Name) then”. tonumber() can change any string variable or instance into a readable format for the computer, so it’s best to use this function when reading numbers off of a string. PaleNoobs 37 — 3y
2 answers
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0
Tonumber() can solve your issue
01 | local rtext = script.Parent.Parent.Random |
02 | local htext = script.Parent |
03 |
04 | htext.Text = tostring(0) |
05 |
06 | while true do |
07 | wait(.01) |
08 | if tonumber(rtext.Text) > tonumber(htext.Text) then |
09 | htext = rtext |
10 | end |
11 | end |
It converts any given value to a number if possible.
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0
Its because rtext doesnt have text, also because you used =, instead of == to compare values. Here is the script btw: I also used A and B instead of rtext and htext, so change it however you'd like.
01 | local A = script.Parent.A |
02 | local B = script.Parent.B |
03 |
04 | B.Text = 0 |
05 | A.Text = 0 |
06 | while true do |
07 | wait(.01) |
08 | if A.Text == B.Text then |
09 | B = A |
10 | end |
11 | end |
0
I meant comparing as in greater (>) or less than (<) jaddub2008 22 — 3y
0
Just Replace (==) with (>) or (<), you just need to make scripts in the TextBoxes to update using basic variables, or do what the other guy said and use Tonumber(). LordKrox 39 — 3y