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How do constantly add numbers without it being the same result?
Hello, I need to be able to print() and make it so that it will count to 100. I was thinking like
1 | for i = 1, 100 do |
2 | a = 0 |
3 | a = a + 1 |
4 | print(a) |
5 | end |
but that doesnt work
Thanks for the help!
An example of the output: 1 2 3 4 5 6 7 ... 99 100
It could even go past 100 to infinity, I don't mind. I just need it to infinitely add. Thanks!
0
Bruh. Dude. Just print i AlexanderYar 788 — 3y
2 answers
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1
Your problem is that every time you run the loop you are setting a back to 0. Instead, do this:
1 | local a = 0 |
2 |
3 | for i = 1, 100 do |
4 | a = a + 1 |
5 | print(a) |
6 | end |
A pretty easy mistake to make and I'm sure everyone has done this before. Let me know if you have any questions about the difference between the two scripts.
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Printing the value of the i variable would work too and it would use less code appxritixn 2235 — 3y
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@phxntxsmic unfortunately there are scenarios that will be more complex than this and will require more than the i value. I decided to help him understand why the value of the variable didnt change cmgtotalyawesome 1418 — 3y
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Please provide explanation with your answers. Simply posting code does not spread knowledge of integral scripting processes which helps people understand the logic and reasoning behind your answer.
1 | A = 0 |
2 | while true do |
3 | A = A + 1 |
4 | print(A) |
5 | wait(0) -- change the 0 to however long you want the wait to be |
6 | end |