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Would this properly run?
`game.Players.LocalPlayer:GetMouse() .KeyDown:connect if string.lower (key) == "m" then Instance.new('Hint', Workspace) Hint.Text = "Just a test"
end end)`
Is this something that can properly run? "Sorry ahead of time for asking, I'm trying to learn on mobile!!"
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if should be on the 2nd line., SprocketSoldier 0 — 9y
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And the ends should be on seperate lines SprocketSoldier 0 — 9y
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You should use the Lua button for multiline code display (it'll look like ~~~~ (newline) code code code (newline) ~~~~~~). The backticks are used for code interspersed with writing (inline code). BlueTaslem 18071 — 9y
1 answer
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3
No, that would not work. Let's highlight the reasons:
game.Players.LocalPlayer:GetMouse() .KeyDown:connect if string.lower (key) == "m" then Instance.new('Hint', Workspace) Hint.Text = "Just a test" end end)
From just looking at that code, you can see a few things.
- You do not properly use the RbxScriptSignal connection.
- You attempt to access key, a nil value.
- You try to set the Text property of Hint, also a nil value.
Now, let's fix those problems and clean up your code a little.
game.Players.LocalPlayer:GetMouse() .KeyDown:connect(function(key)
if key:lower() == "m" then
Instance.new('Hint', Workspace).Text = "Just a test";
end;
end);
Sources to learn from: http://wiki.roblox.com/index.php?title=RBXScriptSignal and http://wiki.roblox.com/index.php?title=Variables
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Ah, ok. And also how come mine didn't show the actual lines of code? SprocketSoldier 0 — 9y