How to check if the child does not have a part?
Hello everyone,
In my code, I would like to check if the parent doesn't an attachment. Since there is a :IsA, I tried to do the opposite. Here is what I can do in javascript:
Javascript:
if !(part.Name == "lkjhgd;") {
//random code....
}
Lua:
for _, v in ipairs(part:GetChildren()) do
if v:IsA("Attachment") then
end
end
So, is there a way I can do that in lua? Thanks for the help!
2 answers
Okay so from my understanding you're trying to check if the part doesn't have a child thats an attachment. In this case its pretty simple to make a check and the rest is up to you.
local function hasAttachment(part)
for _, v in pairs(part:GetChildren()) do
if v:IsA("Attachment") then
return true
end
return false
end
end
if hasAttachment(part) then
print("The part has an attachment!")
else
print("The part doesn't have an attachment!")
end
Sorry if I misinterpreted what you said, reply to my answer if so, otherwise tag me as answered if this solved your issue.
This answer is similar to Bandit's one but there is simpler way to achieve what he has done: FindFirstChildWhichIsA or FindFirstChildOfClass (use the first).
local Attachment = Parent:FindFirstChildWhichIsA('Attachment');
if(Attachment)then;
else
end;
But if you wan't to revert is as you said, !== in JavaScript if i remember correctly, there is keyword not which reverts all given values:
not true -- false
not false -- true
--/In your case:
local Attachment = Parent:FindFirstChildWhichIsA('Attachment');
if(not Attachment)then
print('no attachment');
end
I tried to use code format like in java script so maybe it will look better for you