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How to do that if a minute passed, remove 1 from the minute value?
function doClock(undif)
if debounce2 == false then
local undif = 0
local debounce2 = true
local DefaultTimeMinutes = mapStorage.DefaultTimeMinutes.Value
local MinutesLeft = DefaultTimeMinutes
local SecondsLeft = (MinutesLeft * 60) - 1
local MinutesLeft = MinutesLeft - 1
while SecondsLeft ~= 0 do
local SecondsLeft = SecondsLeft - 1
-- i wanna check if a minute passed, remove 1 from the minute value
wait(1)
end
end
end
Any idea why on how to do that if a minute passed, remove 1 from the minute value? (as said on the comment)
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So I used delay to not stop the entire script while waiting becuase you not only have to subtract seconds but minutes. bruno13bruno13 78 — 4y
1 answer
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Just add a delay() timer. When a certain time passes, an function will execute.
local minutesLeft
local secondsLeft
function removeMinutes()
minutesLeft = minutesLeft - 1
print(minutesLeft.. " minutes and: " .. secondsLeft.. " seconds left.") -- Prints the time left
end
function removeSeconds()
secondsLeft = secondsLeft - 1
print(minutesLeft.. " minutes and: " .. secondsLeft.. " seconds left.") -- Prints the time left.
end
function doClock()
local DefaultTimeMinutes = mapStorage.DefaultTimeMinutes.Value
local MinutesLeft = DefaultTimeMinutes
local secondsM = MinutesLeft * 60
delay(1, removeSeconds())
delay(60, removeMinutes())
end
So what I just made it's use a function called "delay()" that when certain times passes (in seconds, first argument), then a callback will be fired, in this case the functions.
Hope it helped.
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You don't need t print the time left, but it was just to prove the point to you. bruno13bruno13 78 — 4y