I want to get the name of a variable in a table. Here is the script so far
ItemID = {"Nothing", "AHH6", "AK-47", "AK-47S", "AN-94", "AN-94M", "ATHK", "AWP", "DDT Rifle", "M1911", "M1911-M", "M92", "M92-S", "TH3"} --Table IIDV = script.Parent.ItemID --IntValue ItemName = script.Parent.ItemName --StringValue
I want to get the name of the variable, not the index value, to put in the ItemName string value.
I assume u want a list of vars in a list.
Here is an example-
local variables = { var1 = 'nothing'; -- Make sure u add the ; from every var u put var2 = 'AK-47'; } print(variables.var1)
This will output 'nothing'
What you could also do in your case is to do the same thing but add what you want to display.
Here is an example-
local itemName = { item1Name = 'AK47'; item1Name = 'nothing; } local itemNum = { item1Num = 1; item1Name = 2; } IIDV = itemNum.item1Num -- ITEM 1 NUMBER ItemName = itemName.item1Name -- ITEM 1 NAME
Not sure if i understand you correctly but i think i understand what you're asking. You want to get the value of your table and not the index?
If so try this:
local ItemID = {"Nothing", "AHH6", "AK-47", "AK-47S", "AN-94", "AN-94M", "ATHK", "AWP", "DDT Rifle", "M1911", "M1911-M", "M92", "M92-S", "TH3"} --Table local ID_num = 2 -- change this to what index you want but beware if you set this to a value outside the table ie the nhumber of objects it will break the script! local IIDV = script.Parent.ItemID --IntValue local ItemName = ItemID[ID_num] -- AHH6! -- see above! --local ItemName = script.Parent.ItemName --StringValue
If this is not what your asking could you ask a little clearer? so we can help you :)
Got bored decided to make an answer...
local items = {"hello","test1"} for _, v in pairs(items) do if v == "hello" then print('congrats this is way too easy, found "hello"') -- it got hello end end print(items[2]) -- test1 -- solution if you didn't understand above: ItemID = {"Nothing", "AHH6", "AK-47", "AK-47S", "AN-94", "AN-94M", "ATHK", "AWP", "DDT Rifle", "M1911", "M1911-M", "M92", "M92-S", "TH3"} --Table IIDV = script.Parent.ItemID --IntValue ItemName = script.Parent.ItemName --StringValue for _, v in pairs(ItemID) do if v == ItemName.Value then print('got the name.') end end
Basically loop. All the other answers are dictionary and arrays but this is precisely what you want.