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How to add tables in DataStore without overwriting other tables in the DataStore?

Asked by 4 years ago
Edited 4 years ago

So I have been wondering if it is possible to add tables in DataStores. I already used SetAsync to set the first table in the DataStore, which is myTb. I removed SetAsync after that. Here is my code that I tried out:

local dataStore = game:GetService("DataStoreService")
local gds = dataStore:GetDataStore("gds")

local myTb = {{sName = "server", sNum = math.random(1, 9999999), sAvail = true, playersInQueue = {}}}
local key = "figure"

local f = gds:GetAsync(key)
local x = f[1]

for i, v in pairs(f) do
    print(i, v)
end

for i, v in pairs(x) do
    print(i, v)
end

local function updateAvailability(currentValue)
    local serverTable = currentValue[1]
    local serverName = serverTable["sName"]
    local serverNumber = serverTable["sNum"]
    local serverAvail = serverTable["sAvail"]
    local plrsInQ = serverTable["playersInQueue"]

    local updateServerAvailability = {{sName = serverName, sNum = serverNumber, sAvail = false, playersInQueue = plrsInQ}}
    return table.insert(f, updateServerAvailability)
end

local success, newVal = pcall(function()
    gds:UpdateAsync(key, updateAvailability)
end)

if success then
    wait(1)
    local log = gds:GetAsync(key)
    print(#log)
end

At line 36, I am expecting the number of tables in the DataStore table will be two, however, the output says it is only one. Did I make any mistakes in my code?

1 answer

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1
Answered by
Elyzzia 1294 Moderation Voter
4 years ago

on the wiki page for UpdateAsync, it says that the update is cancelled when the function returns nil (aka nothing)

table.insert doesn't return anything, so when you do return table.insert(f, updateServerAvailability), it just returns nil

what you have to do instead is return f itself:

table.insert(f, updateServerAvailability)
return f

if that doesn't make sense, then you should know that tables are each separate objects, like instances; if a and b have the same contents, that doesn't make them equal to each other, and if you set two variables to the same table, a change to one variable will also apply to the other

0
Yes, grind that rep, I'll upvote you along the way greatneil80 2647 — 4y
0
Thank you soooo much! XxThatnaimsterxX 21 — 4y
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