Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
0
How do i make a gui pop up after a certain amount of seconds?
``The script i used:
1 | local GUI = script.Parent.Play |
2 | while true do |
3 | wait(48) |
4 | script.Parent.GUI.Visible = true |
5 | --// And make it invisible again after a certain time |
6 | wait(9999999) |
7 | script.Parent.GUI.Visible = false |
8 | end |
Doesnt work. By the way it might sound dumb since im new to scripting. (Putting full script would help)
3 answers
Log in to vote
1
put a local script inside the screen gui then make the enabled set to false then paste this
1 | while true do |
2 | wait(48) |
3 | script.Parent.Enabled = true |
4 | wait(9999999) |
5 | script.Parent.Enabled = false |
6 | end |
this works because I tested it and know it does.
0
Wow our's are really similar except mine doesn't work because I suck at scripting XD StockBAMBAM 7 — 4y
Log in to vote
1
Please provide explanation with your answers. Simply posting code does not spread knowledge of integral scripting processes which helps people understand the logic and reasoning behind your answer.
I think that I would do
1 | script.Parent.Visible = true |
2 | wait(99999999999) |
3 | script.Parent.Visible = false |
by the way: I don't think it's possible to close a gui. try making a frame and all the content in the frame.
Log in to vote
1
1 | while true do |
2 | wait(48) |
3 | script.Parent.Enabled = true |
4 | --// And make it invisible again after a certain time |
5 | wait(9999999) |
6 | script.Parent.Enabled = false |
7 | end |
put this script in the gui and make the script be a local script