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Why does this error when printing the value of an Vector3Value?
local posTable = {"pos1", "pos2", "pos3", "pos4"}
for i = 1, 24 do
n = math.random(1, #posTable)
pos = posTable[n]
newPos = game.ReplicatedStorage.positions:FindFirstChild(pos)
print("posName: " .. newPos.Name)
print("posValue: " .. newPos.Value)
end
As the title suggests, what is giving me this error?
I get the following output:
posName: pos3
22:18:09.602 - Workspace.Script:8: attempt to concatenate field 'Value' (a userdata value)
22:18:09.602 - Stack Begin
22:18:09.602 - Script 'Workspace.Script', Line 8
22:18:09.603 - Stack End
0
I have everything in the proper hierarchies, as evidenced by the "posName: " line printing properly. OniiCh_n 410 — 9y
1 answer
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2
You're probably used to being able to concatenate a string and a number in Lua.
print("Number: " .. 5)
--> 5
However, userdata isn't automatically converted to a string when concatenated. You have to use the tostring function.
print("Vector3: " .. Vector3.new(5,5,5))
--> error: attempt to concatenate a userdata value
print("Vector3: " .. tostring(Vector3.new(5,5,5)))
--> Vector3: 5, 5, 5
As an alternative, you can use print with a variatic number of arguments. This automatically converts each argument into a string.
print("Vector3: ", Vector3.new(5,5,5))
--> Vector3: 5, 5, 5
1
Thanks for the answer! I never knew about tostring() OniiCh_n 410 — 9y