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How would I round down a decimal with code?
Basically how do I turn 9.12761656 to 9.12? I tried using math.floor but it turns it into an integer. Thanks!
2 answers
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One way would be to multiply it by 100, floor that, then divide it by 100.
9.12761656 * 100 = 912.761656 floor of 912.761656 = 912 912 / 100 = 9.12
Hope this helped
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I've created a function for this, so you are right too, but I have a feeling mine is easier to use. CrastificeDude612 71 — 4y
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I've seen this question before. Here's a quick problem-solver. I've created a function that rounds a long decimal into a short decimal:
local function decimalRound(num,round)
-- Checking if both variables are valid numbers, otherwise throws an error.
assert(tonumber(num),"Variable num is not a number.")
assert(tonumber(round),"Variable round is not a number.")
-- Calculations
local result = num
local roundNum = 10^round
result *= roundNum
result = math.floor(result)
result /= roundNum
-- Return the "result" variable
return result
end
Example of using decimalRound():
local x = decimalRound(9.12761656,2) print(x)
The following example would return:
9.12
No problem, from Canada. :)
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what does assert mean?? CaIcuIati0n 246 — 4y
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^ whenever the first parameter of assert is false or nil, it errors the second parameter brokenVectors 525 — 4y