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How to remove everything after a certain character in a string?
say i have a string like "100 / 100" how would I remove everything after the "/"?
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I just search answer for the same question. Found method for whitespaces string:gsub("(.*)%s.*$","%1") ErtyPL 129 — 2y
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Hey Ho! It seems the easiest way is this one.
local variableName = ("some.string"):gsub("(.*)%..*$","%1") print(variableName)--[[just to check is it working]]
%. stands for the dot operator (...) according to https://www.lua.org/pil/20.2.html
Please accept an answer. Don't fear to ask me directly.
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s = "Deadline is 30/05/1999, firm" date = "%d%d/%d%d/%d%d%d%d" print(string.sub(s, string.find(s, date))) --> 30/05/1999 PROREMIXPL 60 — 2y