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Evaluate if a number is considered a happy number in the least amount of characters?

For more clarification, a number is happy when the sum of the square of all numbers within a given number is equal to 1. If you enter a loop when calculating the happy number, that means the number is unhappy. :(

Print statements are not part of your character count. Your code should explicitly state if the number is happy or otherwise.

Example: 19 -> (1^2 + 9 ^2) = 82 -> (8^2 + 2^2) = 68 -> (6^2 + 8^2) = 100 -> (1^2 + 0^2 + 0^2) = 1. This means that 19 is a happy number.

Shortest and most valid answer within a week gets the solution. If you've gotten an answer on the Discord, you are not a valid contester. I'll update the question with my implementation within due time.

And, before you prepare your moderation voter hammer, it's in-line with all rules and regulations. I checked thrice.

Cheers.

My answer:

local t,y,b,x={},tonumber,29;function h(n)if(t[n])then;return(false)end;t[n]="";b=0;for _ in(tostring(n):gmatch('%d'))do;b=b+(y(_)or(0))^2;end;if(b<=1)then;return("")end;print(b)return(h(b))end;print(h(b)~=false)

1 answer

✓ Accepted answer

I did it: here is my solution.

function isHappy(originalNumber)
	local pattern = {};
	function calculate(number)
		local squaredSum = 0;
		for num in tostring(number):gmatch("(%d)") do --parses a number to individual digits
			squaredSum = squaredSum + (tonumber(num) ^ 2) 
		end
		
		------------uhhhhhhh------------
		if(not pattern[tostring(squaredSum)]) then
			pattern[tostring(squaredSum)] = 0;
		end
		pattern[tostring(squaredSum)] = pattern[tostring(squaredSum)] + 1;
		---------EEEEEEEE------------
		if(squaredSum == 1) then
			return true
		elseif(pattern[tostring(squaredSum)] > 1) then
			return false
		else
			return calculate(squaredSum)
		end
	end
	
	local _isHappy  = calculate(originalNumber)
	if(_isHappy) then
		print(originalNumber, " is happy (:")
	else
		print(originalNumber, " is sad ):")
	end
end

isHappy(10) --happy
isHappy(12) --sad

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