I am trying to use a Conditional Statement on two tables. it checks if there contents are the same, here is a sample of my code:
local Table1 = { }
local Table2 = { }
if Table1 ~= Table2 then
print("The Content of both Tables is different")
end
However, the game keeps thinking the two Tables contents are different, is there anyway i can fix this, thanks
local table1 = {"Two", "Strings"}
local table2 = {"Two", "Strings"}
local match = false
for i = 1, #table1 do
match = false
for ind, v in pairs(table2) do
if table1[i] == v then
match = true
break
end
end
if match == false then
print("Does not match")
break
end
end
On the 2 first lines we declare our tables.
Then we make a variable equal to false.
Then we make a loop that will run an equal amount of times as there are values in table1.
In the beginning of the loop we once again set the value of our variable, match to false. Then we make a second loop inside of our first one that will run an equal amount of times as there are values in table2. That loop will check if there is any value in table2 that matches the current value of table1. If it does, it will set the value of match to true to announce that there was a match. But if there wasn't any value that matched. Our first loop will break and print that the tables do not contain the same values.
too long, try my code
There is really nothing wrong with this. You can't downvote just because you think your code is better
what's wrrong with this answer? why do u just randomly down vote?
bepis
pepsi
Thanks for the help
You're welcome
well the thing is doing {} == {} will always be false.. the == operator checks to see if it's (table)operands are the same object, not wheather they have the same content..
so if i did, local a = {x = 10} and local b = {x = 10}, then print(a == b) will always print false..
however, if i did b = a then it print(a == b) will return true because the statement implies that a IS b..
to check whether or not 2 tables have the same content, you'd have to do something like the following.
function isSame(tableA, tableB)
for index, value in pairs(tableB) do
if(tableA[index] == value) then
return true
end
end
return true
end
but this might not work if the table passed to pairs has less items than the other table, and the items that it has match some of the few that the other one has
local table1, table2 = {},{}
for i,v in ipairs(table1) do
if table2[i] = table1[i] then
print(v..' matches in table2')
end
end
Its pretty basic. If table2 finds something in table1, it prints that value.
why do randomly downvote @Spjureeedd's answer? -_-
I apreciate it Arsubia (but it was an answer)
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4 comments
If you do print(Table1) and print(Table2) it won't print the same in the output.
I can only think of a somewhat complicated loop to find out if your table's contents are the same. But I'm sure someone will give you a better answer
You are trying to print if the hexadecimal address is the same for the tables which isn't true you can create a nested loop though.
Wow... 3 answers... this is sad