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All questions/Question #98261
✓ ANSWER ACCEPTED

How do I make the newer items go on top of the older items using UIListLayout?

Asked 835 views1 answers

So I'm making this ChatLogs Gui, and I have a problem with it; the new items that get added inside the scrolling gui go below the older items. I also forgot to say there is UIListLayout inside the scrolling frame. Since the newer items go below the older items, I have to scroll all the way down to see the new stuff. I've messed around with the properties of the UIListLayout, but everything I tried didn't work. Click Here to see what it looks like.

Another thing, I did find https://developer.roblox.com/en-us/api-reference/property/UIGridStyleLayout/SortOrder and saw the code sample that shows how to do it, but It's confusing to me. In conclusion, I just want a simple explanation of how to make the newer items go above the older items using UIListLayout.

Anonymous

1 answer

✓ Accepted answer

the SortOrder enum doesn't have any useful value for this case, so i'd approach this by getting the array of all items and parent them to nil then, add which ever item i want on top in the array at the beginning, and once again parent all the item to the gui that holds displays them..

I know this is a hurdle to speed, and general efficiency, but at times, u have to sacrifice some things for others.

AnonymousPermalink

5 comments

0

also, make sure the SortOrder enum is set to Custom

Anonymous#
0

wdym custom? I don't see something saying custom

Anonymous#
0

i dont remember what it displays in studio, just make sre its not set to Name

Anonymous#
0

Thanks! I tried something similar to it, and it worked!

Anonymous#
0

np

Anonymous#

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