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✓ ANSWER ACCEPTED

How may I make a group rank's Access a door with a clickdetector?

Asked 852 views1 answers

The base of this script is to operate a door, At a group, with a certain ranks number. But the door does not work

local group = 3444858
local rank = (255 or 239 or 240 or 241 or 242 or 243 or 244 or 245 or 246 or 247 or 248 or 249 or 250 or 251 or 252 or 253 or 254)

function onClicked(player)
	if not player then return end
	if player:GetRankInGroup(group) >= rank then
	if script.Parent.Open.Value == false then
		script.Parent.Open.Value = true
		script.Parent.Transparency = 1
		script.Parent.CanCollide = false
		print('Opened')
	elseif script.Parent.Open.Value == true then
		script.Parent.Open.Value = false
		script.Parent.Transparency = 0
		script.Parent.CanCollide = true
		print('Closed')
	end
	else
		print('NOT IN GROUP!')
	end
	end
script.Parent.ClickDetector.MouseClick:connect(onClicked)

It does work with only One ranks, But i need multiple ranks in the group.

Which as the script doesn't seem to work with multiple ranks then more then one.

Anonymous

1 answer

✓ Accepted answer

you dont need to put ALL the numbers in the table. just get the lowest number and do this:

function onClicked(player)
	if not player then return end
	if player:GetRankInGroup(group) >= 239 then
	if script.Parent.Open.Value == false then

and, the correct format for a table looks like this:

local ranks = {255,254,253,252,251,250,249,248,247,246,245,244,243,242,241,240,239}

and, in case if you dont want a certain rank to not be allowed to pass the door, just do this:

function onClicked(player)
	if not player then return end
	local rank = player:GetRankInGroup(group)
	if rank >= 239 and not rank == 255  then --doesnt let rank 255 in
	if script.Parent.Open.Value == false then

in case you want to scan all the numbers in the table ranks:

local ranks = {255,254,253,252,251,250,249,248,247,246,245,244,243,242,241,240,239}
function onClicked(player)
	if not player then return end
	local rank = player:GetRankInGroup(group)
	for i,v in pairs(ranks) do --scans thru all values in table ranks, therefore I meaning index (the number being scanned) and V meaning Value, the object/string/number being scanned.
		if rank == v then
		if script.Parent.Open.Value == false then

i hope that helped :p

AnonymousEdited Permalink

1 comment

0

Welp, That changed everything! Thank You so much for the Assistance & Use of proper table!

Anonymous#

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