script.Parent.ClickDetector.MouseClick:Connect(function()
if(game.Workspace.Light_Stat_1.BrickColor == BrickColor.new("Lime green"))then
print("hi2")
local Lift1 = Instance.new("Part")
Lift1.Parent = game.Workspace
Lift1.Shape = "Cylinder"
Lift1.Anchored = true
Lift1.CanCollide = true
Lift1.Size = Vector3.new(7.75, 12.06, 10.04)
Lift1.Position = Vector3.new(-89.933, 3.925, 215.561)
Lift1.Name = "Lift1"
end
end)
COMMUNITY QUESTION
What is wrong with this code here? try to check if brickcolor is equal to lime green.
1 answer
Your BrickColor isn't Lime green because I just tested with part and works for me:
if game.Workspace.Part.BrickColor == BrickColor.new("Fossil") then
print("Test")
end
-- Prints Test
2 comments
0
This is the only answer that makes sense. His conditional statement is just fine. It may not be visually appealing but the syntax is right.
0
Ya but it is a button i made so when i press it it check if it is lime green then mades a part but it starts as really red
This discussion is preserved as it was. New answers, comments, and votes are closed.
5 comments
So it sure be like when you click it check for lime green then runs the code down below that.
Try using "BrickColor.new(1020)"
You mans a genuis
use this for colors: https://developer.roblox.com/en-us/articles/BrickColor-Codes
One Question how would i loop this untill it is that color?