How to Make a Abbriviated Leaderbaord?

Here is a much easier way

local function cnvrt (n, precission)
    precission = precission or 1;
    if (n >= 10^9) then
        return string.format("%." .. precission .. "fb", n / 10^9)
    elseif (n >= 10^6) then
        return string.format("%." .. precission .. "fm", n / 10^6)
    elseif (n >= 10^3) then
        return string.format("%." .. precission .. "fk", n / 10^3)
    else 
        return tostring(n);
    end
end

print(cnvrt(1548034, 1));
print(cnvrt(17478, 2));

THANK YOU TO GoldAngelInDisguise

For remaking the function, fully working.

here is the code and example of it being ran.

local num = 1239887.45

function ab(num, ignore)
   local fnum = math.floor(num)
   local snum = tostring(fnum)
   local d = 0
   while num >= 1 do
       num = num / 10
       d = d + 1
   end
   num = math.floor(num / 10 ^ (-ignore) + 0.5) * 10 ^ (d - ignore)
   if #snum <= 6 and #snum > 3 then
      local abnum = (num/1000).."K"
      return abnum
   elseif #snum >= 7 then
      local abnum = (num / 1000000).."M"
      return abnum
   end
end

My function:

local num = 1239887.45

function ab(num, ignore)
   local fnum = math.floor(num)
   local snum = tostring(fnum)
   if #snum <= 6 and #snum > 3 then
      local abnum = string.sub(tostring(fnum/1000), 1, ignore + 1).."K"
      return abnum
   elseif #snum >= 7 then
      local abnum = string.sub(tostring(fnum/1000000), 1, ignore + 1).."M"
      return abnum
   end
end

print(ab(num, 0))

made this function in a hurry, basically it simplifies your number and also ignores a certain amount of characters depending on the "ignore" you set.

In the above example, ignore is set to 0 and it will return "1M".

Set it to something high to not ignore anything, and a few if you want to ignore only a few.

Ok I now have time to explain what everything does.

So first we create the function with the number and ignore parameter which will allow the function to well.. function, and be called.

We create fnum, which is a math.floor version of the number to help us see how many characters are in the number using snum, which is transforming the number to a string and then counting the characters.

In the first if statement we check if it's over 999 and under 999,999. (higher than 3 characters, lower or equal to 6 characters).

We then create 'abnum' which is a combination of multiple things, string.sub, concatenation, a division and a transformation from number to string, in order to get everything we need.

by using fnum/division we get what the number would be if it was shortened with "K" or "M". after that we turn it into a string to allow us to combine with with the keyword we want and then use string.sub, what we want to do is use ignore to ignore a certain amount of characters, so it isn't filled with a bunch of decimals, this is something you'll have to work on so it doesn't just return num.M/K

if you set the ignore to a certain number you could get something like "1.M" in the above example it'd be 1.

You need to check for the . and add another character to the ignore so it appears as num.decimal K/M

this was just an example function I made for you, you can perfect it and change it to resolve the problem i told you about above.