So I want to make a script that makes the game pick 1+ player randomly and is not the same person the game chose before.
✓ ANSWER ACCEPTED
How do I make the game choose more than 1 random player?
2 answers
✓ Accepted answer
Make a list of all the players and randomly pick. After picking a player, remove them from the list
local PlayerList = {}
local function refresh()
PlayerList = {}
for _, plr in pairs(game.Players:GetChildren()) do --for every child (player) of the game.Players
table.insert(PlayerList, plr.Name) --add the player's name to the list
end
end
local function RandomPlayer()
local num = math.random(1, #PlayerList) --get a random index number
local player = PlayerList[num] --Get player with that index number
for index, plr in pairs(PlayerList) do --Go through every player in the list
if plr == player then --When the player is found...
table.remove(PlayerList, index) --remove them from the list and...
return game.Players[player] --return the player's instance
end
end
end
Here are the functions you need
2 comments
0
Well thanks but where do I put the script that the random players will do?
0
It depends on what you are doing. Usually for this stuff, you put a script in the ServerScriptService
To randomly pick a player, do:
local Players = game:GetService('Players')
local playerList = Players:GetPlayers()
local randomPlayer = playerList[math.random(1, #playerList)]
To make it not pick the previous player, store the previous player as a variable and compare it with the new player:
local Players = game:GetService('Players')
local previousPlayer
repeat
local playerList = Players:GetPlayers()
local randomPlayer = playerList[math.random(1, #playerList)]
until (previousPlayer ~= randomPlayer)
previousPlayer = randomPlayer
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1 comment
good luck