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✓ ANSWER ACCEPTED

how to put a cooldown on Tween?

Asked 787 views1 answers

Hello!

I would like to know how I can put a timeout in the time that the block is to return to where it was.

when the interpolation ends at the indicated position when I activated the option "Reverse" (true) It does not wait for 1 second and returns to the position it was in. How can I make him wait a few seconds and then go back to where he was?

Script:

local Part1, Part2 = script.Parent.PartA, script.Parent.PartB;

local tweenInfo = TweenInfo.new(
	
	2,
	Enum.EasingStyle.Linear,
	Enum.EasingDirection.Out,
	0,
	true,
	2
)



local a = TweenService:Create(Part1, tweenInfo, {Position = Vector3.new(81, 5, 197)})
local b = TweenService:Create(Part2, tweenInfo, {Position = Vector3.new(99, 5, 203)})

while wait()do
	
	a:Play()
	b:Play()
end
AnonymousEdited

1 comment

0

use a wait(1)

Anonymous#

1 answer

✓ Accepted answer

If you want the part to go back after a certain timeout, you will need to split tween to 2 separate tweens:

local Part1, Part2 = script.Parent.PartA, script.Parent.PartB;

local tweenTime = 2
local cooldown = 2

local tweenInfo = TweenInfo.new(

    tweenTime,
    Enum.EasingStyle.Linear

)


local aStartingPosition = Part1.Position
local bStartingPosition = Part2.Position
local a = TweenService:Create(Part1, tweenInfo, {Position = Vector3.new(81, 5, 197)})
local aReverse = TweenService:Create(Part1, tweenInfo, {Position = aStartingPosition})
local b = TweenService:Create(Part2, tweenInfo, {Position = Vector3.new(99, 5, 203)})
local bReverse = TweenService:Create(Part2, tweenInfo, {Position = bStartingPosition})

while wait() do

	a:Play()
	b:Play()

	wait(tweenTime + cooldown) 
	
	aReverse:Play()
	bReverse:Play()

	wait(tweenTime + cooldown)

end

Just remeber that playing a tween does not yield the thread, so you need to add tween time to cooldown time, before playing reverse tween.

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