I'm not sure if there is a way to format numbers so you can have a max of 2 decimal places. Any help is appreciated. Thanks.
EDIT: I realize I could simply do the math, then make it a string and use substring to shorten it to two decimal points and store it in a string instead of a number, but I was wondering if there was a more efficient way of doing this.
A simple way is to use math.floor with some easy math.
function RoundToPlace(Num, Place)
return math.floor(Num * (10^Place)) / (10^Place)
end
print(RoundToPlace(1/3, 2)) --> 0.33
print(RoundToPlace(1/3, 5)) --> 0.33333
print(RoundToPlace(5, 2)) --> 5
You can by using string.sub! Here's how:
local num = 5.4547784
function getDec(n)
local temp = tostring(num)
local dec = 0
for i=1,string.len(temp) do
if string.sub(temp, i, i) == '.' then
dec = i
break
end
end
if dec ~= 0 then
return tonumber(string.sub(temp, 1, dec+2))
else
return num
end
end
print(getDec(num))
EDIT ON YOUR EDIT: This method will work no matter where the '.' is. 500.323 or 3.232
EDIT #2: Fixed it so it won't mess up on numbers without a decimal.
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2 comments
Lol, I literally posted a second before you about substring. If there isn't an answer that has a better way, I will accept this.
I really appreciate the thought and work you have put into this, but 18cwatford's answer is shorter, more efficient, and it stays in a number value. Upvoted because it was still a great answer.