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✓ ANSWER ACCEPTED

How can you deal with large numbers?

Asked 302 views2 answers

Hello, i have the following issue.

my game allows player to get a very large score having 10 digits in the leader board looks ridicules so i came up with the following solution

	if n > 1000 then
		return math.floor(n / 1000) .. "K"
	elseif n > 1000000 then
		return math.floor(n / 1000000) .. "M"
	else
		return n .. ""
	end

the issue is where should i place the statement?

should i make it into a function then call it every time a script changes to score value? or is there a way to run something everytime a value is changed?

Anonymous

2 comments

0

You can make a NumberValue (an actual physical object) that contains the player's score and use the the Changed event on that. I don't really use dataStore or leaderboards much so I couldn't tell you exacty where to store the NumberValue, that's up to you.

Anonymous#
0

Slightly off topic but you need to check for n > 1000000 first instead of n > 1000 because if the score is 100000000 for example it still uses K instead of M.

Anonymous#

2 answers

✓ Accepted answer

If you store the number in a IntValue object then you can create a listener for when the IntValues value changes

local intvalue = Instance.new("IntValue")

scoreboardCalculations = function()

	if n > 1000 then
	    return math.floor(n / 1000) .. "K"
	elseif n > 1000000 then
	    return math.floor(n / 1000000) .. "M"
	else
	    return n .. ""
	end

end

intvalue.Changed:Connect(scoreboardCalculations)

The code might need a little cleaning up i'm working off a crappy tablet Hope this helped

AnonymousEdited Permalink

2 comments

0

is Instance.new not Instance.New

Anonymous#
0

intvalue.Changed:Connect(scoreboardCalculations()) is running the function not passing the function to the Changed event

Anonymous#

You can convert the value to string then use the length of the string to get the correct unit.

Example

local unitTable = {"K","M"} -- unit list

local function formatNumber(val)
	-- count the string length take 1 to give us the base 3 count
	-- math.floor is the same as v - (v % 1)
	local unit = math.floor((#tostring(val) - 1) / 3)
	
	if unitTable[unit] then
		-- return a string with the correct using using ^ for devision
		return tostring(math.floor( val / (1000 ^ unit))) .. unitTable[unit]
	end
	
	return tostring(val) 
end

for i=0, 1000000, 100 do
	print(formatNumber(i))
end

Hope this helps.

AnonymousEdited Permalink

1 comment

0

^

Anonymous#

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