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✓ ANSWER ACCEPTED

How to remove a value in a table without using position?

Asked 252 views1 answers

I am trying to make a randomizer that draws a number and then a button that removes a value in an array.

This is the code that is triggered by pressing the brick that picks a random number from the table.

values = {"2", "7", "0", "5", "3", "X", "X", "X"}

function draw()
	script.Parent.Value.Value = values[math.random(#values)]
	script.Parent.Chip.SurfaceGui.TextLabel.Text = script.Parent.Value.Value 
end
script.Parent.Button.ClickDetector.MouseClick:Connect(draw)

And this is the other code that is supposed to remove the specific value. It is fired by a different brick.

function show2()
	table.remove(values, 1)
	game.Workspace.Digits.Two.Transparency=0.8
	wait(0.05)
	game.Workspace.Digits.Two.Transparency=0.6
	wait(0.05)
	game.Workspace.Digits.Two.Transparency=0.4
	wait(0.05)
	game.Workspace.Digits.Two.Transparency=0.2
	wait(0.05)
	game.Workspace.Digits.Two.Transparency=0
	wait(0.05)
end
script.Parent.firstnumber.ClickDetector.MouseClick:Connect(show2)

The 2 will be removed and 7 will take its place. But I have another block of code that is supposed to remove 7 when I press another button.

Is this possible to do?

AnonymousEdited

1 answer

✓ Accepted answer

You can use this function to remove a value from a table:

function removeVal(tablee, value) -- second array is the value you want to find in the table (can be a string, object, number, etc)
	for i, v in pairs(tablee) do 
		if v == value then 
			print("removing " .. tostring(value))
			table.remove(tablee, i) -- 'i' is the position of the found variable in the table
		end
	end
end

--Example:
local Values = {"2", 7", "0", "5", "3", "X", "X", "X"}
removeVal(Values, "2")
AnonymousPermalink

1 comment

0

Thank you!

Anonymous#

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