--<tkcmdr>--
local door = script.Parent
local bool = true
local bool2 = true
local clearance = {
["[SCP] Card-Omni"] = true,
["[SCP] Card-L5"] = true,
["[SCP] Card-L4"] = true,
["[SCP] Card-L3"] = true,
["[SCP] Card-L2"] = false,
["[SCP] Card-L1"] = false,
["[SCP] MTF Access Card"] = false,
["[SCP] O5-2 Access Card"] = true,
["[SCP] ET Card"] = false,
["[SCP] Card-Dev"] = true
}
function openDoor()
script.Parent.DoorOpen:play()
for i = 1,(door.Size.z / 0.12) do
door.CFrame = door.CFrame - (door.CFrame.lookVector * 0.12)
wait()
end
door.Transparency = 1
for i,v in pairs(door:GetChildren()) do
if v:IsA("Decal") then
v.Transparency = 1
end
end
wait(3)
door.Transparency = 0
for i,v in pairs(door:GetChildren()) do
if v:IsA("Decal") then
v.Transparency = 0
end
end
script.Parent.DoorClose:play()
for i = 1,(door.Size.z / 0.12) do
wait()
door.CFrame = door.CFrame + (door.CFrame.lookVector * 0.12)
end
end
script.Parent.Parent.Door.touched:connect(function(hit)
if hit.Parent:FindFirstChild('Humanoid') and bool then
local plr = workspace[hit.Parent.Name]
local player = game.Players:GetPlayerFromCharacter(plr)
if player.Name == "tictac67" or "tolly67" or "MINECRAFT_LOLBUILDZ" then
bool = false
script.Parent.AccessGranted:Play()
openDoor()
wait(1)
bool = true
elseif player.Name ~= "tictac67" or "tolly67" or "MINECRAFT_LOLBUILDZ" and bool2 then
bool2 = false
script.Parent.AccessDenied:play()
wait(1)
bool2 = true
end
end
end)
✓ ANSWER ACCEPTED
This door opens for everyone not just the people in the list. Any idea why?
2 answers
✓ Accepted answer
The problem is in your if statements. When you are using or you are forgetting that it is a whole new check system. Let me explain with a little code:
--here is an if statement:
if player.Name == "Name" then -- this works
--let's create a new if statement but this time with two names
if player.Name == "Name" or "Name2" then -- this always lets the player through.
-- Why?!?! ugh this is so frustrating
The reason is that when you use or you are in essence creating a new if statement. It is like saying:
if "Name2" then
and that will always pass. Why? Because a string is truthy. It is not false or nil and seems true to the if statement because it exists. What you will need to do is:
if player.Name == "Name" or player.Name == "Name2" then
and it works. There is a problem though. If you have a lot of names this will take forever to write and will look extremely ugly. I recommend having a table of names and looping through it. Here is the function I use:
local admins = {"Name1", "Name2"}
local function isAdmin(plr)
for i,v in pairs(admins) do
if v == plr.Name then
return true
end
end
return false
end
if isAdmin(player) then
-- this is a cleaner way to do it when you have a lot of names. Maybe not so worth it if you have two names. But three and beyond can benefit.
Hope this helps and have a great day scripting!
As far as I am concerned, more then 1 "or" statement doesn't work... Correct me if I am wrong, but I am pretty sure. So line 49 and 55 are not working.
This discussion is preserved as it was. New answers, comments, and votes are closed.
1 comment
This is a common problem. I recommend learning a bit more about or/and statements.