I have table.
local foodList = {
["Apple"] = {"rbxassetid://923453681", "rbxassetid://923453682", Vector3.new(1,1,1)},
["Pineaple"] = {"rbxassetid://677816839", "rbxassetid://677816891", Vector3.new(1,2,1)},
}
print(#foodList)
-- Will be 0, not 2
Why not 2?
The problem here is that they have names. #table will return the amount of elements when they don't have names, such aslocal foodList = {"Apple","Banana"}
However, in your situation you are using an array with names. A quick work around for that is to make a function that returns the amount of elements in an array.
function tableSize(input)
local size = 0
for i,v in pairs(input) do
size = size + 1
end
return size
end
local foodList = {["Apple"] ={"rbxassetid://923453681","rbxassetid://923453682", "fsa"},["Pineaple"] = {"rbxassetid://677816839", "rbxassetid://677816891","fsa"}}
print(#foodList)
print(tableSize(foodList))
Output:
0
2
If you need anymore help just ask! :D
Basically Lua is really dumb, so rather than make # mean "size" like any normal human being capable of any modicum of rational thought would expect, it only deals with integer indices starting from 1.
function dictionaryCount(d)
count = 0
for key, value in pairs(d) do
count = count + 1
end
return count
end
That should do what you want.
However, bare in mind that while the execution of # is basically free, and doesn't change no matter how large the table, the execution of dictionaryCount scales linearly with how many things are in the table.
If you're familiar with big-O notation, dictionaryCount(d) is O(n)
I wanted to use "for do" for this, but I thought it wouldn't work. Thanks for explaining.
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1 comment
Oooooh. Thank you for useful information!