Scripting HelpersARCHIVE
A little piece of Roblox history. Preserved for everyone, one question at a time.Read about the archive →
All questions/Question #61696
✓ ANSWER ACCEPTED

Is There A Way To Condense These Tables?

Asked 142 views4 answers

Not much to explain but is there any way to make this more efficient? Each succeeding line is the same but with one added value. There ought to be a way to make this take up less lines and space. Is there?

local tier1Food = {'FrenchBread'}

local tier2Food = {'FrenchBread', 'Muffin'}

local tier3Food = {'FrenchBread', 'Muffin', 'Donut'}

local tier4Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie'}

local tier5Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel'}

local tier6Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee'}

local tier7Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin'}

local tier8Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie'}

local tier9Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant'}

local tier10Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake'}

local tier11Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake'}

local tier12Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea'}

local tier13Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake'}

local tier14Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie'}

local tier15Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie', 'BlueberryPie'}

local tier16Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie', 'BlueberryPie', 'StrawberryPie'}
Anonymous

2 comments

0

How are these tables being used? Are you using them to know what types of food(s) that the tiers can specifically access?

Anonymous#
0

Thank you everyone who submitted answers. I apologize for being unclear about my intentions with the tables but every answer worked as I intended.

Anonymous#

4 answers

✓ Accepted answer

Hi Bunny,

You can simply store all of the foods in one table and make a system that returns the correct table according to the tier you want. Something like this:

local food_system = {

	foods = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie', 'BlueberryPie', 'StrawberryPie'};

	tier_return = function(self, tier)
		local tab_to_return = {};
	
		for i = 1, tier do
			tab_to_return[i] = self.foods[i];
		end
	
		return tab_to_return;
	end
}

local tier_5_tab = food_system:tier_return(5);

for _, food in next, tier_5_tab do
	print(food);
end

##Well, hope I helped and have a nice day/night.

Thanks,

Best regards,

~~ KingLoneCat

AnonymousPermalink

2 comments

0

Note although this method is straightfoward, you create a new table every time you get a tier. This can eat up memory if you perform a large amount of "tier returns". To resolve this, create a table to store tiers that were already created, and check there first before creating a new one. Check out my answer for an example of this.

Anonymous#
0

But, this gets the tier table when it's needed. Not create one for each tier. Creating one for each tier can also eat up a lot of memory on a bigger scale. Also, the table I create inside of the function gets over-ridden and why would you need to keep creating a new table everytime you get a tier? Just make a reference to the tier table for later usage. So, you won't have to keep calling it.

Anonymous#

Regardless of your purpose, you should only use one table, containing all the foods in order.

From there, it depends on what you want to do.

If you absolutely need a table for each tier, then examine my function below called getTier. It returns whichever tier you want, given a number in range.

Since I am not sure what you are doing, I cannot necessarily give you more than that without shooting in the dark.

What the function does, is either gets the existing tierTable, or creates it based off the number you put into the function.

local Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie', 'BlueberryPie', 'StrawberryPie'}

local tierTables = {}

local function getTier(num)
    if num > 0 and num <= #Food then
        if tierTables[num] then
            return tieirTables[num]
        else
            tierTables[num] = {}
            for i = 1, num do
                tierTables[num][i] = Food[i]
            end
            return tierTables[num]
        end
    end
end

--Example usage, say I just wanted tier6
local tier6 = getTier(6)

If you have any questions let me know.

AnonymousPermalink

yes, but this is all you can do

local foods = {
 tier1Food = {'FrenchBread'}; -- use " ; " when putting tables in tables
tier2Food = {'FrenchBread', 'Muffin'};
tier3Food = {'FrenchBread', 'Muffin', 'Donut'};{'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie'};
tier5Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel'};
tier6Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee'};
tier7Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin'};
tier8Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie'};
tier9Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant'};
tier10Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake'};
tier11Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake'};
tier12Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea'};
tier13Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake'};
tier14Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie'};
tier15Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie', 'BlueberryPie'};
tier16Food = {'FrenchBread', 'Muffin', 'Donut', 'ChocolateChipCookie', 'Bagel', 'Coffee', 'Muffin', 'ApplePie', 'Croissant', 'VanillaCake', 'Cupcake', 'Tea', 'ChocolateCake', 'PumpkinPie', 'BlueberryPie', 'StrawberryPie'} -- " ; " not needed on last line

}
-- to access these do

--foods.tier1Food
AnonymousEdited Permalink

2 comments

1

Uh, how is this "condensing" his tables? I'm pretty sure he wanted it so you don't need a table for each tier.

Anonymous#
0

What he wanted was instead of a billion tables was to have one.

Anonymous#

I didn’t read through it all, but I’m just assuming there’s another item for each rank. This was typed on an iPad, so it might not work. 

local food = { "food", "food2", "etc"}
function GetAvaliableFood(rank)
     local foodAvaliable = {}
     for i=1, rank do
          table.insert(foodAvaliable, food[i])
     end
     return foodAvaliable
end
AnonymousPermalink

This discussion is preserved as it was. New answers, comments, and votes are closed.