How check if a string is nan (not a number) ?

Asked Jun 6, 20181,096 views2 answers

The title explain everything.

I tried this :

local V = "145"
	if (V) == "number" then
		print("V is a number")
	else
		print("V is not a number")
	end
end)

AnonymousJun 6, 2018

I think you meant to use type or typeof ?

AnonymousJun 6, 2018#

2 answers

✓ Accepted answer

You can use type() to get the type of a value.

local V = 145

    if type(V) == "number" then
        print("V is a number")
    else
        print("V is not a number")
    end

AnonymousJun 6, 2018Edited Jun 6, 2018Permalink

worked thanks !

AnonymousJun 6, 2018#

Np :P

AnonymousJun 6, 2018#

You guys make no sense. Downvoting something that works? You guys have brain damage.

AnonymousApr 5, 2019#

You can use tonumber() to check if a string can be converted to a number.

local V = "145"
    if tonumber(V) then
        print("V is a number")
    else
        print("V is not a number")
    end
end)

Thanks

AnonymousJun 7, 2018#

That's really stupid.

AnonymousApr 5, 2019#

Use type().

AnonymousApr 5, 2019#

tonumber is faster and requires less typing

AnonymousJun 26, 2020#

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