Hi, I'm trying to find a way to divide the amount of given players in half when placing them on certain teams.
This is my code:
local player = game.Players:GetPlayers()
[math.random(2,#game.Players:GetPlayers())]
player.TeamColor = BrickColor.new("Bright green")
As you can see, the obvious issue is that if the game only had 2 players, they'd both be on one team. I'm not sure how to do this, so any help is greatly appreciated.
Hey, I have made the script for you. If you have any questions, please ask me.
--Get the Player count
local playercount = #game.Players:GetChildren()
--Calculate how many players should go on the team
--Is the number even?
if playercount % 2 == 0 then
--number is even
local playersselected = 0
local toselectplayers = playercount / 2
for i, v in pairs(game.Players:GetChildren()) do
if playersselected < toselectplayers then
v.Neutral = false
v.TeamColor = BrickColor.new("Bright green")
playersselected = playersselected + 1
end
end
else
--number is odd
local playersselected = 0
local toselectplayers = playercount / 2 + 0.5
for i, v in pairs(game.Players:GetChildren()) do
if playersselected < toselectplayers then
v.Neutral = false
v.TeamColor = BrickColor.new("Bright green")
playersselected = playersselected + 1
end
end
end
Thank you, this worked.
Glad I could help you :D
Just a tip, you can do local toselectplayers = math.ceil(playercount/2) instead of local toselectplayers = playercount / 2 + 0.5, this will round the number up, math.floor() will round it down.
Thanks! I didn't know that!
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2 comments
Maybe try checking the amount of people on both teams and if one is higher than the other, then place them on the opposite side
I'm working on the script for you, I'm almost done.