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[SOLVED] How can you make for example 1.298018197102000063e+42 a normal number?

Asked by 2 years ago
Edited 2 years ago

I have a problem, I tried to make a K,M,B system, but there is a problem, roblox changes big numbers to numbers like this one --> 1.298018197102000063e+42. But I convert it to a string, so my script sees the number like 1.2 --> wich will result in something like 1K.

This is very annoying, so my question is, is there any way to change them back in a script? (I tried searching for it but I don't know how it's called if there is a name for it).

The script works fine when roblox didn't change the value

(This is my script)

local module = {}

local HighNumbers = {
    ['K'] = 1000,
    ['M'] = 1000000,
    ['B'] = 1000000000,
    ['T'] = 1000000000000,
    ['Qd'] = 1000000000000000,
    ['Qn'] = 1000000000000000000,
    ['Sx'] = 1000000000000000000000,
    ['Sp'] = 1000000000000000000000000,
    ['O'] = 10000000000000000000000000000,
    ['N'] = 10000000000000000000000000000000,
    ['D'] = 10000000000000000000000000000000000,
    ['Ud'] = 1000000000000000000000000000000000000,
    ['TdD'] = 100000000000000000000000000000000000000,
    ['QdD'] = 100000000000000000000000000000000000000000,
    ['QnD'] = 100000000000000000000000000000000000000000000,
    ['SxD'] = 100000000000000000000000000000000000000000000000,
    ['SpD'] = 100000000000000000000000000000000000000000000000000,
    ['SpD'] =   1000000000000000000000000000000000000000000000000000,
    ['OcD'] =   1000000000000000000000000000000000000000000000000000000,
    ['NvD'] =   1000000000000000000000000000000000000000000000000000000000,
    ['VgN'] =   1000000000000000000000000000000000000000000000000000000000000,
    ['UvG'] =   1000000000000000000000000000000000000000000000000000000000000000,
    ['DvG'] =   1000000000000000000000000000000000000000000000000000000000000000000,
    ['TvG'] =   1000000000000000000000000000000000000000000000000000000000000000000000,
    ['QtV'] =   1000000000000000000000000000000000000000000000000000000000000000000000000,
    ['QnV'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000,
    ['SeV'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000000,
    ['SpG'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000000000,
    ['OvG'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000000000000,
    ['NvG'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000,
    ['TgN'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000,
    ['UtG'] =   1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
}

local HighestNum = 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
local HighestName = 'UtG'
local HC = 999

local Pattern = '%d+'

function module.Convert(Number)
    for i,v in pairs(HighNumbers) do
        local Rounded = tostring(Number/v):match(Pattern) --> It goes wrong here
        --warn('n '..Number..'v '..v..'r '..Rounded)
        local RoundedNum = tonumber(Rounded)
        warn(Number)
        if Number >= v and RoundedNum and RoundedNum < 1000 and Number >= 1000 and Number < HighestNum * HC then        
            local Result = Rounded..i   
            warn(Result)
            return Result
        elseif Number < 1000 then
            warn(Number)
            return Number
        elseif Number > HighestNum * HC then
            warn(Number/HighestNum..HighestName)
            return Number/HighestNum..HighestName
        end
    end
end

return module

EDIT: Thanks to MCAndRobloxUnited I found the solution:

Cannot copy the solution, but go take a look at string.format, you can find it there --> Works great

IF ANYONE HAS TROUBLE WITH THIS, YOU CAN EITHER REPLY TO THIS OR SEND ME A MESSAGE TO ME (/MY ROBLOX PROFILE)

0
why go past KMBT tho. scientific notation is properly concise for big numbers. cabbler 1937 — 2y
0
It's because the game I'm working on purpose is to make as much money as possible, so, is there a way to make it a number again, even if it requeres more string manipulation? RedcommanderV2 1256 — 2y

2 answers

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Answered by 2 years ago

1.298018197102000063e+42 is actually 1.298018197102000063 * 10^42. Just for easier maths.

Hope this helps!

0
Like I said, it's already solved, I already firgured out it was the scientific notation and I used some string patterns to make it a normal notation again RedcommanderV2 1256 — 2y
0
That's great to hear! I just noticed that edit though... Good luck with your scripts! lazycoolboy500 537 — 2y
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Answered by 2 years ago

I know that you said this question was solved, but I thought I would post an interesting solution I found for people who need to know this kind of thing and find your question. Here is how I overcame this problem:

    money.Changed:Connect(function()

        local amountLableFound = false

        for i = 3, 12, 3 do 

            if money.Value >= (10 ^ i) and money.Value < (10 ^ (i + 3)) then

                amountLableFound = true

                local uncheckedMVariable = (math.floor(money.Value / (10 ^ (i - 2))) / 100) 
                local strMVariable = tostring(uncheckedMVariable)
                local decimalCheck = string.find(strMVariable, "%.")
                local mVariable

                if decimalCheck and decimalCheck ~= 4 then

                    mVariable = string.sub(strMVariable, 1, 4)

                else

                    mVariable = string.sub(strMVariable, 1, 3)

                end

                if money.Value > (uncheckedMVariable * (10 ^ (i - 2)) * 100) then

                    if money.Value >= (10 ^ 12) then

                        cash.Value = mVariable.."T+"

                    elseif money.Value >= (10 ^ 9) then

                        cash.Value = mVariable.."B+"

                    elseif money.Value >= (10 ^ 6) then

                        cash.Value = mVariable.."M+"

                    elseif money.Value >= (10 ^ 3) then 

                        cash.Value = mVariable.."K+"

                    end

                else

                    if money.Value >= (10 ^ 12) then

                        cash.Value = mVariable.."T"

                    elseif money.Value >= (10 ^ 9) then

                        cash.Value = mVariable.."B"

                    elseif money.Value >= (10 ^ 6) then

                        cash.Value = mVariable.."M"

                    elseif money.Value >= (10 ^ 3) then 

                        cash.Value = mVariable.."K"

                    end

                end 

            end

        end

        if not amountLableFound then

            cash.Value = math.floor(money.Value)

        end

    end)

Note: cash is a string value and money is a number value. cash is what displays on the leaderboard. If you need larger amounts just add on to the length of the for loop and add on an elseif. I hope you find this helpful(to anyone who finds this). I also hope that you find this interesting @RedcommanderV2.

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