(SOLVED) How to find the least distance within magnitude?

It feels like this is the easiest task that LUA could do, but somewhy I just cannot figure it out. I believe the easiest way would be listing the found HumanoidRootParts magnitudes in an array, then using math.min() to find the least argument. But how to create this array? Or is there a simpler way?

This is what I have; Searches through workspaces models, finding HumanoidRootParts, then calculating the magnitudes between player and found HumanoidRootParts. How to make the code find out which of the parts is closest?

descendants = game.Workspace:GetDescendants()
		for index, descendant in pairs(descendants) do
			if descendant.ClassName == "Model"
			then
				local keppi = descendant:FindFirstChild("HumanoidRootPart")
				if keppi then
				local magnitude = (player.Character.HumanoidRootPart.Position - keppi.Position).magnitude
					if magnitude <= 20 and magnitude >= 1 then
						print(keppi.Parent.Name.." is close as heck")
							foundtarget = keppi
					end
				end
			end
		end

Thanks in advance!

Solution:

	--foundtarget = player.Character.Head
	--local bestmagn = 20
		
	local descendants = game.Workspace:GetDescendants()
		for index, descendant in pairs(descendants) do
			if descendant.ClassName == "Model"
			then
				local keppi = descendant:FindFirstChild("HumanoidRootPart")
				if keppi then
				local magnitude = (player.Character.HumanoidRootPart.Position - keppi.Position).magnitude
					if magnitude <= 20 and magnitude >= 1 then
						print(keppi.Parent.Name.." is close as heck")
							--if magnitude <= bestmagn then
								--print("better solution found")
								--bestmagn = magnitude
								--foundtarget = keppi
							end
					end
				end
			end
		end

Added parts commented in above script. With the help of TheeDeathCaster and Cabbler, I added a value that changes if any of the nearby parts are closer than the required 20, in the meanwhile it stores the best magnitudes parent to foundtarget value, which is then later used in code.