How to position something according to if a number is even or odd?

For every item in a player's backpack, a frame is created. After that, the frame is positioned horizontally. What I need help on is the positioning. If the number of frames is odd, like 1 or 3, to place the middle frame in the middle. But if the number of frames/items is even, like 2 or 4, then make the frames equidistance to the center.

Here is a visual concept, + = center.

						+
Odd(3Frames):	 F		F		F 
Even(2Frames):		F		F

Hi,

One way to do this is using the modulo operation. The modulo is the remainder of two numbers, so if you take n%2 where n is your number, you will see if it is even (if the remainder is 0) or odd (if it is not 1). Then you just need an if statement.

if (number%2 == 0) then --even number
	frame.Position = frameposition1
else --odd number
	frame.Position = frameposition2
end

In pseudocode:

-- Store n elements in an array
elements = {e_1, e_2, ..., e_n}
-- Division is the gap between each element
division <- total screen width / number of elements

-- If odd, start at position 0, otherwise at offset
if number is odd
    -- Start at the edge of the screen
    element_position <- 0
else
    -- Start half way through a division, giving a buffer of half a division either side
    element_position <- division / 2

-- Place elements on screen
for i = 1 to n
    e_1.placeAt(element_position)
    element_position = element_position + division

I imagine something along those lines would work.