How do you find out which value in a table has occurred the most?

You could make a simple frequency table like so.

local numbers = {10, 10, 12, 12, 15, 10}

function Count(num)
	for _, num in pairs(num) do
		if script:FindFirstChild(num) then
			script[num].Value = script[num].Value + 1
		else
			local new = Instance.new('IntValue', script).Name = num
			new.Value = 1
		end
	end
	local results = {}
	for _, num in pairs(count) do
		results[tostring(num)] = script[num].Value
	end
	return results --Returns a dictionary of all values that have been requested to track. Have not been tested.
end

print(Count(numbers)[10])

This would print "Ten : 3, Twelve : 2".

Also, math.random needs rather 0 parameters or 2, not 1. You can do

local anum = math.random()
print(anum)

and that would print decimal numbers from 0 to 1, or have numbers between two numbers like

local anum = math.random(1, 10)
print(anum)

This would not print decimals, however print a number from 1 to 10. Also, use math.randomseed. It randomizes your math.random statements. To make the most random numbers that is NOT predictable what will happen even if you know what time it is, nor using math.random, I do

math.randomseed(tick() / wait() * wait() % wait() ^ wait() - wait() + wait())

If you dont know already, wait() returns a number how long it actually waited. Sometimes they have to hold off the task because something else is running and they cannot handle running another task at the moment. Even in a plain baseplate game, this will always be different. All those operators do not have to be in order, they are just there to make it random.

Also, math.randomseed needs to be before you do math.random like

math.randomseed(tick() / wait() * wait() % wait() ^ wait() - wait() + wait())
print(math.random(1, 10)
print(math.random(1, 10)
print(math.random(1, 10)
print(math.random(1, 10)
print(math.random(1, 10)
print(math.random(1, 10)
print(math.random(1, 10)
print(math.random(1, 10)

Hope this helps!